1.

Find the integrals of the functions tan4x

Answer»

∫tan4xdx

= ∫(sec2x - 1)tan2x.dx

= ∫sec2x.tan2x - ∫tan2x.dx

= ∫(tanx)2sec2x - ∫(sec2x - 1)dx

\(= \frac{tan^3x}{3} - tanx + x + c\)



Discussion

No Comment Found