find the largest 4 digit no which when divided by 4 , 7 ,13 leaves a remainder of 3 in each case

find the largest 4 digit no which when divided by 4 , 7 ,13 leaves a r

1.	find the largest 4 digit no which when divided by 4 , 7 ,13 leaves a remainder of 3 in each case
Answer» \xa0LCM of ( 4,7,13) = 364Largest 4 digit number = 9999On dividing 9999 by 364 we get remainder as 171Greatest number of 4 digits divisible by 4, 7 and 13 = (9999 – 171) = 9828Hence, required number = (9828 + 3) = 9831Therefore 9831 is the number.