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find the largest no which divides 615 and 963 leaving the remainder 6 in each case |
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Answer» To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.Consider HCF be x.In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6\xa0from both the cases.609 = 3 x 3 x 29957= 3 x 11 x 29⇒ x = 3 x 29 = 87∴\xa0largest number which divides 615 and 963 leaving remainder 6 in each case is 87. Maths exam is over bro now next is hindi see the date sheet 87... |
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