Find the LCM of x^2 - 4 and x^4 - 16

1.	Find the LCM of x^2 - 4 and x^4 - 16
Answer» X²-4=x²-2²=(x-2) (x+2) X⁴-16= (x²) ² -4²= (x²-4) (x²+4) =( x²-2²) (x+4) = (x-2) (x+2) (x+4) In both (x-2) (x+2) is commonSo we can write lcm as (x-2) (x+2) then one more valu is there that is ( x+4) Now LCM= (x-2) (x+2) (x+4)

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