Saved Bookmarks
| 1. |
Find the maximum and minimum value of 3cosx + 4sinx + 8 |
| Answer» Minimum value of an equation of the form a cosx+b sinx+c is{tex}c-\\sqrt{a^2+b^2}{/tex}Here,c=8 a=3 b=4=> minimum value=\xa0{tex}8-\\sqrt{3^2+4^2}{/tex}=> minimum value= 8 - 5= 3 | |