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Find the maximum power which can be transmitted by means of a steel shaft rotating about its axis with an angular velocity `omega=120rad//s`, if its length `l=200cm`, radius `r=1.50cm`, and the permissible torsion angle `varphi=2.5^@`. |
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Answer» The maximum power that can be transmitted by means of a shaft rotating about its axis is clearly `Nomega` where N is the moment of the couple producing the maximum permissible torsion `varphi`. Thus `P=(pir^4Gvarphi)/(2l)*omega=16*9kw` |
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