Find the minimum value of x2 – 13x + 36.1. -25/42. -16/53. 25/44. 16

1.	Find the minimum value of x2 – 13x + 36.1. -25/42. -16/53. 25/44. 16/5
Answer» Correct Answer - Option 1 : -25/4 Given: The polynomial is x² – 13x + 36 Formula Used: If polynomial ax² + bx + c, then Min/Max value of polynomial = c – b²/4a Calculation: For polynomial x² – 13x + 36 a = 1, b = -13, and c = 36 Minimum value of the polynomial = c – b²/4a ⇒ 36 – (-13)²/4 × 1 ⇒ (36 × 4 – 169)/4 ⇒ (144 – 169)/4 ⇒ -25/4 ∴ The minimum value of x² – 13x + 36 is -25/4.

Find the minimum value of x2 – 13x + 36.1. -25/42. -16/53. 25/44. 16/5

Answer» Correct Answer - Option 1 : -25/4

Given:

The polynomial is x² – 13x + 36

Formula Used:

If polynomial ax² + bx + c, then

Min/Max value of polynomial = c – b²/4a

Calculation:

For polynomial x² – 13x + 36

a = 1, b = -13, and c = 36

Minimum value of the polynomial = c – b²/4a

⇒ 36 – (-13)²/4 × 1

⇒ (36 × 4 – 169)/4

⇒ (144 – 169)/4

⇒ -25/4

∴ The minimum value of x² – 13x + 36 is -25/4.

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Find the minimum value of x2 – 13x + 36.1. -25/42. -16/53. 25/44. 16/5

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