1.

Find the minor of the element of second row and third column (a23) in the following determinant :\(\begin{vmatrix}2 & -3 & 5 \\[0.3em]6 & 0 & 4 \\[0.3em]1 &5 &-7\end{vmatrix}\)

Answer»

We have,

\(\begin{vmatrix} 2 & -3 & 5 \\[0.3em] 6 & 0 & 4 \\[0.3em] 1 &5 &-7 \end{vmatrix}\) 

Minor of an element a23 = M23 

\(\begin{vmatrix} 2 & -3 \\[0.3em] 1 & 5 \\[0.3em] \end{vmatrix}\) 

= 10 + 3 = 13



Discussion

No Comment Found