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Find the nature of roots 1) x^2- 8x + 16 = 02) 2x^2 - 2x + 1= 0 |
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Answer» 2) a = 2, b = -2, c = 1 D = b^2 - 4ac D = (-2)^2 - 4 x 2 x 1 D = 4 - 8 D = -4 Therefore, there are no real roots. 1) a = 1, b = -8, c = 16 D = b^2 - 4ac D = (-8)^2 - 4 x 1 x 16 D = 64 - 64 D = 0 Therefore, there are real and equal roots. |
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