Find the nature of roots of ax2+bx+c=0,a>0,b=0,c>0

1.	Find the nature of roots of ax2+bx+c=0,a>0,b=0,c>0
Answer» The disscriment of this quadratic will be:D=b^2-4acD=(0)^2-4(a)(c)D= -4acThe value of "d" is negetive So no real root Roots will be unreal.

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