InterviewSolution
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InterviewSolution
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Find the nature of the equation 2X^2-5X-7=0. |
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Answer» 2x^2-5x-7x=02x^2-5x-7(2x^2-7x)+(2x-7)x(2x-7)+1(2x-7)(x+1)(2x-7) Answer:the roots are not realStep-by-step explanation:comparing the equation in ax^2+bx+c=0a=2b=-5c=7Delta =b^2-4ac =25-4 x 2 x 7 =25-56 = -31It describes that the roots are imaginary or do not exist . Answer:the roots are real and equalStep-by-step explanation:comparing the equation in ax^2+bx+c=0a=2b=-5c=7Delta =b^2-4ac =25-4 x 2 x 7 =25-56 = -31It describes that the roots are imaginary or do not exist . |
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