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| 1. |
Find the next term of AP : root 7, root 28 ,root 63 ,.......... |
| Answer» Here,{tex}a = \\sqrt { 7 } , a + d = \\sqrt { 28 }{/tex}{tex}\\therefore \\quad d = \\sqrt { 28 } - \\sqrt { 7 } {/tex}{tex}= 2 \\sqrt { 7 } - \\sqrt { 7 }{/tex}{tex}= \\sqrt { 7 }{/tex}or, Next term =\xa0{tex}\\sqrt { 63 } + \\sqrt { 7 }{/tex}or, = {tex}\\sqrt { 9\\times7 } + \\sqrt { 7 }{/tex}or,\xa0{tex}= 3 \\sqrt { 7 } + \\sqrt { 7 } {/tex}or, {tex}= 4 \\sqrt { 7 }{/tex}or,\xa0{tex}= \\sqrt { 7 \\times 16 }{/tex}{tex}= \\sqrt { 112 }{/tex}So, next term is {tex}\\sqrt { 112 }{/tex}. | |