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| 1. |
Find the no. Of three digit natural no. Which are divisible by 11 |
| Answer» Three digit natural numbers are 100,101,102.....,998,999. From which,\xa0multiples of 11 are 110, 121, 132, ...., 990.so,this forms an AP 110,121....,990.\xa0where, first term ({tex}a {/tex})=110 and common difference({tex}d{/tex})=121-110=11, last term({tex}l{/tex}) = 990..Let,\xa0{tex}l = {a_n} = a + (n - 1)d{/tex}{tex}\\therefore 990 = 110 + (n - 1) \\times 11{/tex}{tex} \\Rightarrow n = 81{/tex}There are 81 three - digit numbers which are divisible by 11. | |