Find the number Of all 3 Digit natural numbers which are divisible by

1.	Find the number Of all 3 Digit natural numbers which are divisible by 9
Answer» a=108 , d=9 , an=999, then find n with formula an=a+(n-1)d , the final answer is n= 100 Bro first find the smallest and largest 3digit terms divisible by 9 then use formula of AP for finding THE nth term \'An=A1+(n-1)d where A1 is the smallest 3digit term divisible by 9 An is the largest 3 digit term and d is the common difference \'9\'

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