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Find the number of natural numbers between 101 and 999 which are divisible by both 2 and 5 |
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Answer» 89 natural numberexplanation:- no. divisible by 2&5 must be divisible by 10 Form an AP of natural number present between 101 & 999AP = 110, 120, 130,............, 990from the AP we concluded a = 110d= 10nth term of the AP = 990a+(n-1)d=990110+(n-1)10=990(n-1)10=990-110(n-1)= 880/10n-1=88n=88+1n=89natural number present between 101 & 109 = 89 99 |
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