Saved Bookmarks
| 1. |
Find the number of terms in the finite AP 3,6,9....111. |
| Answer» So, first term = a = 3Common difference = d = 3Last term = Tn = 111Let number of terms be n.Now, Tn = a + (n-1)dSo, 111 = 3 + (n-1)×3So, 108 = 3×(n-1)So, 108/3 = n-1So, n-1 = 36So, n = 37Thus, number if terms is 37. | |