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Find the perimeter of triangle with vertices (0,4) (0,0) and (3,0)

Answer» First find length of each sides of ∆Let A( 4 , 0) B(0, 0) and C (0 , 3)use distance formula,AB =√(4²+0) =4BC= √(0+3²) = 3CA =√(4²+3²) =5now ,perimeter of ∆ = 3 + 4 + 5= 12 unit


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