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| 1. |
Find the point on the x-axis which is equidistant from (2,-5) and (-2, 9) |
| Answer» Now, the point is on x-axis, so the value \'y\' of the given point will be zero.Let, the value of the \'x\' value of the given point = x[Assume,x as a variable to do the further mathematical calculations.]So,the point is = (x,0)As mentioned in the question,the two points are equidistant from (x,0).So,Distance between (x,0) and (2,-5)= ✓(x-2)²+(0+5)²Distance between (x,0) and (-2,9).=✓(x+2)²+(0-9)²Now,the points are equidistant.So,✓(x-2)²+(0+5)² = ✓(x+2)²+(0-9)²(x-2)²+(0+5)² = (x+2)²+(0-9)²x²-4x+4+25 = x²+4x+4+81x²-4x-x²-4x = 4+81-4-25-8x = 56x = -7 | |