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Find the point on the x-axis which is equidistant from the point A(-2,3) B(5,4) |
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Answer» Danish Ali you answer is right Noo A (-2,3) B (5,4) so, = root (-2-5)square + (3-4)square root 49+1=root ka 50 ans I am confuse for this answer 3 line equation Correct option isA(2,0)AC=BC\xa0(Equidistance)AC2=BC2(x−5)2+(0−4)2=(x+2)2+(0−3)2x2−10x+25+16=x2+4+4x+9−14x+41−13=0−14x+28=0=14x=−28x=28/14x=2\u200b |
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