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| 1. |
Find the point on x-axis which is equidistant from points (-1,0) and (5,0) |
| Answer» Let A(x,o) be any point on the X-axis , which is equidistant from points (-1,0) and (5,0).{tex}\\Rightarrow (x+1)^2=(x-5)^2{/tex}⇒ x2 + 2x + 1 = x2 - 10x + 25⇒ 2x + 1 = -10x + 25⇒ 2x + 10x = 25 - 1⇒ 12x = 24⇒ x = 24/12{tex}\\Rightarrow x= 2{/tex}Therefore , Required point is (2,0). | |