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| 1. |
Find the point on y axis which is equidistant from points (5,-2) and(-3,2) |
| Answer» Let suppose the point on Y axis is ASo the A(0,y)(5,-2) = P(-3,2)=QAP²= AQ²..(Equidistant point)By distance formula(0-5)² + [(y-(-2)]²=[(0-(-3)]² + (y-2)²25+y²+4y+4 = 9+ y²-4y+44y +4y=9-25 ......(like term)8y=-16y=-16/8y=-2A(0,-2) | |