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Find the positive root of √3 X square + 6 is equal to 9

Answer» {tex}\\sqrt { 3 x ^ { 2 } + 6 } = 9{/tex}3x2 + 6 = 813x2 = 81 - 6 = 75x2\xa0= 25{tex}\\therefore{/tex}\xa0x = ± 5Hence, Positive root = 5


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