1.

Find the positive root of 3x²+6=9

Answer» 1
3x2 + 6x = 93x2 + 6x - 9 = 03x2 + 9x - 3x - 9 = 03x(x + 3) - 3 (x +3) = 0(x + 3) ( 3x - 3)= 0x + 3 = 0 or 3x - 3 = 0x = -3 or 3x = 3x = -3 or x = 3/3 = 1
3x^2 + 6 =93x^2 = 9-63x^2 =3x^2 =3/3x^2 =1x= root 1So positive root is +1 and negative root is -1


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