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Find the positive root of 3xsquare +6x-9=0 |
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Answer» 3x² + 6x - 9 = 0 ,,3x² + 9x - 3x - 9 = 0 ,,3x ( x + 3 ) - 3 ( x + 3 ) ,,= (3x - 3 ) ( x + 3 ) = 0 ,, = x = 3/3 = 1 . ,,,, x = - 3 .,,,,First root is [ x = 1] ,, second root is [ x = - 3 ] .So , the positive root of. 3x² + 6x - 9 = 0 is 1 Ans . Thank you. 3x2\xa0+ 6x = 93x2\xa0+ 6x - 9 = 03x2\xa0+ 9x - 3x - 9 = 03x(x + 3) - 3 (x +3) = 0(x + 3) ( 3x - 3)= 0x + 3 = 0 or 3x - 3 = 0x = -3 or 3x = 3x = -3 or x = 3/3 = 1 |
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