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| 1. |
Find the positive values of m for which the distance between the points A(3,1)B(13,m)is 10 unit |
| Answer» Distance formula=\xa0√ (x2\xa0- x1)2 + ( y2\xa0- y1)2Distance = 10 units√ (13-3)2\xa0+ (m-1)2 = 10√ (10)2\xa0\xa0+ m2\xa0+ (1)2\xa0- 2(m)(1) = 10 Squaring both sides(10)2\xa0\xa0+ m2\xa0+ (1)2\xa0- 2(m)(1) = (10)2 100 + m2\xa0+ 1 - 2m = 100 m2\xa0-2m + 1 = 100 - 100 m2\xa0-2m+1 = 0 m2\xa0- 1m - 1m +1 =0 m (m -1) -1( m-1) =0 ( m-1) (m-1) =0 m-1=0 Therefore, m= 1 | |