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Find the principal solutions of the equation sec x = -2.(a) 2π/3, 4π/3(b) 2π/3, 5π/3(c) 4π/3, 5π/3(d) π/3, 5π/3This question was addressed to me in semester exam.The doubt is from Trigonometric Equations in section Trigonometric Functions of Mathematics – Class 11

Answer»

Right OPTION is (a) 2π/3, 4π/3

Best explanation: SINCE SEC X is negative in 2^nd and 3^rd QUADRANT so, there are two principal solutions to above equation i.e. x = π – π/3, π + π/3. So, x=2π/3, 4π/3.



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