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| 1. |
Find the probability that a non leap year chosen at random has\xa0\t52 Sundays\t53 Sundays |
| Answer» 2) A non-leap year has 365 daysA year has 52 weeks. Hence there will be 52 Sundays for sure.52 weeks = 52 x 7 = 364 days .365– 364 = 1day extra.In a non-leap year there will be 52 Sundays and 1day will be left.This 1 day can be\xa0Sunday, Monday,\xa0Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.Of these total 7 outcomes, the favourable outcomes are 1.Hence the probability of getting 53 sundays = 1 / 7.1)∴ probability of getting 52 sundays = 1 - 1/ 7 = 6 / 7. | |