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Find the quadrant of a circle whose circumference is 22 cm |
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Answer» 77/8 cm² Solution:Let the radius of the circle be \'r\' Thus, the circumference C = 2πrTherefore, r = C/2πA quadrant of a circle means one of the four equal parts. Therefore, the area of a quadrant = 1/4 × Area of a circle = 1/4 × πr2Circumference (C) = 22 cmTherefore, radius (r) = C/2π= 22/(2 × 22/7)= (22 × 7)/(2 × 22)= 7/2 cmTherefore, the area of a quadrant = 1/4 × πr2= 1/4 × 22/7 × 7/2 × 7/2= 77/8 cm2 77/8 |
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