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Find the quadratic equation whose zeros are2 and -6

Answer» K(x2-(x+y)x +xy) K[x2-(2+(-6))x +(2*-6)] K[x2-(2-6)x +(-12)] K[x2-(-4)x -12]k[x2+4x-12]put k=1Hence the polynomial is x2+4x-12


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