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| 1. |
Find the quadric polynomial whose zeroes are 2+√3 And 2-√3 |
| Answer» Since there are 2 zeroes, the polynomial is of degree 2.Let a and b represents the zeroes of the polynomial.Let {tex}a=2+\\sqrt{3} and b=2-\\sqrt{3}{/tex}Since, the polynomial is of degree 2Polynomial would be of the form {tex}{x^{2}-(a+b) x+a b} {/tex}Therefore computing the values,{tex}{a+b=(2+\\sqrt{3})+(2-\\sqrt{3})=4}{/tex}\xa0{tex}{a b=(2+\\sqrt{3}) \\times(2-\\sqrt{3})=4-3=1}{/tex}Therefore, the polynomial is {tex}{x^{2}-4 x+1} {/tex} | |