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Find the ratio in which p p(4,m)divides the line segment joining the point m(2,3)(6,-3)

Answer» Let us assume that point P divides the line segment AB in the ratio (k : 1)Using section formula,P(4, m) =\xa0{tex}\\frac{6k+2}{k+1} , {/tex}{tex}\\frac{-3k+3}{k+1}{/tex}{tex}\\therefore{/tex}\xa0{tex}\\frac{6 \\mathrm{k}+2}{\\mathrm{k}+1}{/tex}\xa0= 4\xa0{tex}\\Rightarrow 6k+2=4k+4 \\Rightarrow 2k=2{/tex}{tex}\\Rightarrow{/tex}\xa0k = 1{tex}\\therefore{/tex}\xa0The ratio is 1 : 1Now, m =\xa0{tex}\\frac{-3k+3}{k+1}{/tex}\xa0=\xa0{tex}\\frac{-3+3}{2}{/tex} = 0


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