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Find the real no. whose product with irrational number, 4-√3 is 39

Answer» {tex}\\begin{array}{l}Let\\;the\\;number\\;is\\;x\\\\so\\;x(4-\\sqrt3)=39\\\\x=\\frac{39}{(4-\\sqrt3)}=\\frac{39(4+\\sqrt3)}{(4-\\sqrt3)(4+\\sqrt{3)}}=\\frac{39(4+\\sqrt3)}{16-3}\\\\=\\frac{39(4+\\sqrt3)}{13}=3(4+\\sqrt3)\\\\\\end{array}{/tex}


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