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Find the real values of x and y for which:x + 4yi = ix + y + 3 |
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Answer» Given: x + 4yi = ix + y + 3 or x + 4yi = ix + (y + 3) Comparing the real parts, we get x = y + 3 Or x – y = 3 …(i) Comparing the imaginary parts, we get 4y = x …(ii) Putting the value of x = 4y in eq. (i), we get 4y – y = 3 ⇒ 3y = 3 ⇒ y = 1 Putting the value of y = 1 in eq. (ii), we get x = 4(1) = 4 Hence, the value of x = 4 and y = 1 |
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