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If ω is the complex cube root of unity, find the value of ω2 + ω3 + ω4 |
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Answer» ω is the complex cube root of unity. ω3 = 1 and 1 + ω + ω2 = 0 Also, 1 + ω2 = -ω, 1 + ω = -ω2 and ω + ω2 = -1 ω2 + ω3 + ω4 = ω2 (1 + ω + ω2 ) = ω2 (0) = 0 |
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