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If (a + ib)(c + id){e + if) (g + ih) = A + iB then show that (a2 + b2)(c2 + d2)(e2 + f2) (g2 + h2) = A2 + B2 |
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Answer» Given: A + iB = (a + ib)(c + id)(e + if)(g + ih) ∴ A-iB = (a- ib)(c – id)(e – if)(g – ih) But A2 + B2 = (A + iB)(A – iB) = (a2 + b2)(c2 + d2)(c2 + f2)(g2 + h2) |
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