Find the root of the equation 16x-10/x=27

1.	Find the root of the equation 16x-10/x=27
Answer» 16x-10/x = 2716 x2\xa0-10 = 27 x16x2\xa0-27x -10 = 0Here a= 16, b= -27 and c= -10x= -b+√ b2\xa0- 4ac/ 2a and x = -b-√b2-4ac/2ax = -(-27)+√(-27)2\xa0-4 16(-10)/ 216 and x= -(-27) - √(-27)2\xa0-416-10/216x= 27 +√729+640/32 and x = 27-√729+640/32x = 27+37/32 and x = 27-37/32x = 64/32 and x = -10/32x = 2 and x = -5/16\xa0\xa0

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