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Find the root of the quadratic equations by using the quadratic formula :- 2x^-3x-5=0

Answer» here ,, discriminant = (b^2 - 4ac ) = (-3 )^2 + (4×2×5) = 49Quadratic formula:x = (-b +or- root of B^3 - 4ac )÷ by 2a1. X = (3 + root of 49)÷ 4 =2.52. X= ( 3- root of 49) ÷ 4 = -4÷4 -1
a=2 , b=-3 , c=-5D=b^-4acD=2^-4×2×-5D=4+40D=44,D<0,two distinct rootQuadratic formula = -b±√D/2a= -(-3)±√44/2×2X=3+2√11/4 , X=3-2√11/4


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