InterviewSolution
Saved Bookmarks
| 1. |
Find the roots of equation: a2x2 – 3abx + 2b2 = 0.1. 2b/a, b/a2. a/b, b/a3. 2a/b, a/b4. -2b/a, a/b |
|
Answer» Correct Answer - Option 1 : 2b/a, b/a Given: a2x2 – 3abx + 2b2 = 0 Concept used: By using factorization method (Middle term split) Calculation: a2x2 – 3abx + 2b2 = 0 ⇒ a2x2 – 2abx – abx + 2b2 = 0 ⇒ ax(ax – 2b) – b(ax – 2b) = 0 ⇒ (ax – 2b)(ax – b) = 0 ⇒ (ax – 2b) = 0 or (ax – b) = 0 ⇒ x = 2b/a or x = b/a ∴ The roots of equation are 2b/a and b/a. |
|