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Find the roots of equation: a2x2 – 3abx + 2b2 = 0.1. 2b/a, b/a2. a/b, b/a3. 2a/b, a/b4. -2b/a, a/b

Answer» Correct Answer - Option 1 : 2b/a, b/a

Given:

a2x2 – 3abx + 2b2 = 0

Concept used:

By using factorization method (Middle term split)

Calculation:

a2x2 – 3abx + 2b2 = 0

⇒ a2x2 – 2abx – abx + 2b2 = 0

⇒ ax(ax – 2b) – b(ax – 2b) = 0

⇒ (ax – 2b)(ax – b) = 0

⇒ (ax – 2b) = 0 or (ax – b) = 0

⇒ x = 2b/a or x = b/a

The roots of equation are 2b/a and b/a.



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