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Find the roots of following quadratic equation - ( x+3) (x+1)=3(X- 1/3)

Answer» (x+3) (x-1) = x-1/3x2\xa0- x + 3x - 3 = x-1/3x2\xa0+ 2x - 3 = x-1/33x2\xa0+ 6x- 9 = x-13x2+ 5 x - 8 = 03x2+ 8x - 3x - 8 = 0x(3x + 8) - 1(3x + 8) = 0(3x + 8) (x - 1 ) = 0x = -8/3 , 1So the roots are -8/3 and 1


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