Find the roots of the equation x2+3x-(m+2)(m+5)=0 where m is constant

1.	Find the roots of the equation x2+3x-(m+2)(m+5)=0 where m is constant
Answer» x2 +3x - (m+2)(m+5) = 0⇒ x2 + (m+5)x - (m+2)x - (m+2)(m+5) = 0⇒ x (x + m+5) - (m+2)(x+m+5) = 0⇒ (x+m+5)(x-m-2) = 0⇒ x = - m-5. and m+2Roots are (-m-5) and (m+2)

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