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| 1. |
Find the roots of the quadratic equation 3x²-2√6x+2=0 |
| Answer» 3-2√6x+2=03-√6x-√6x+2=0√3*√3-√3x*√2x-√3x*√2x+√2*√2=0√3x(√3x-√2)-√2(√3x-√2)=0(√3x-√2)(√3x-√2)=0x=√2/√3Therefore the equation has two equal roots;\xa0√2/√3 | |