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| 1. |
Find the roots of the quadratic equation x square + (a+b ÷ a+a÷a+b)x +1=0 |
| Answer» {tex}x ^ { 2 } + \\left( \\frac { a } { a + b } + \\frac { a + b } { a } \\right) x + 1 = 0{/tex}{tex}x ^ { 2 } + \\frac { a } { a + b } x + \\frac { a + b } { a } x + 1 = 0{/tex}{tex}x \\left( x + \\frac { a } { a + b } \\right) + \\frac { a + b } { a } \\left( x + \\frac { a } { a + b } \\right) = 0{/tex}{tex}\\left( x + \\frac { a } { a + b } \\right) \\left( x + \\frac { a + b } { a } \\right) = 0{/tex}{tex}\\therefore{/tex}\xa0{tex}x = \\frac { - a } { a + b } , \\frac { - ( a + b ) } { a }{/tex} | |