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| 1. |
Find the smallest integral value of `x`satisfying `(x-2)^(x^2-6x+8))>1` |
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Answer» `(x-2)^(x^2-6x+8)` 1)`x-2<1` `x^2-6x+8>0` `x^2-4x-2x+8>0` `(x-4)(x-2)>0` `x in (-oo.2)(4,oo)` `x in(4,oo)` 2)`x-2<1` `x<3` `x-6x+8<0` `(x-4)(x-2)<0` `x in(2,4)` `x in(2,3)` `x in(2,-3)uu(4,p)` `5`. |
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