1.

Find the smallest integral value of `x`satisfying `(x-2)^(x^2-6x+8))>1`

Answer» `(x-2)^(x^2-6x+8)`
1)`x-2<1`
`x^2-6x+8>0`
`x^2-4x-2x+8>0`
`(x-4)(x-2)>0`
`x in (-oo.2)(4,oo)`
`x in(4,oo)`
2)`x-2<1`
`x<3`
`x-6x+8<0`
`(x-4)(x-2)<0`
`x in(2,4)`
`x in(2,3)`
`x in(2,-3)uu(4,p)`
`5`.


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