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Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 respectively. |
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Answer» sankey sanket Ayush sanket <“https://images.app.goo.gl/eaJm55Pj3HSHpkne6"> =\'\'https://images.app.goo.gl/eaJm55Pj3HSHpkne6\'\' 28-8=20 & 32-12=20 So the reqd no will be 20 less than the L. C. M. of 28 and 32 . L. C. M. of 28 & 32 is = 224 Reqd smallest no =224-20 = 204. |
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