Find the smallest number which leves reminder 8and12 when division by

1.	Find the smallest number which leves reminder 8and12 when division by 28 and 32 respectively?
Answer» First, we find L.C.M of 28 and 32 28= 2 . 2 . 732= 2 . 2 . 2 . 2 . 2 L. C. M (28,32)= 2 . 2 . 2 . 2 . 2 . 7=224The smallest number that leaves remainder 8 and 12 when divided by 28 and 32 = 224 -(8+12) = 204Thus, 204 is required smallest number.

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