Find the smallest number which when divided by 28 and 32 leaves remain

1.	Find the smallest number which when divided by 28 and 32 leaves remainder 8 and 12 respectively.
Answer» divisor is 28 and remainder is 8. Difference is 20 (28-8)divisor is 32 and remainder is 12. Difference is 20 (32-12)You can see that the difference is 20 in both the cases.LCM of divisors - difference ,or, LCM (28, 32) - 20 = 224 - 20 = 204So, the number is 204

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