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| 1. |
Find the smallest value of k for real roots xsqure-kx+9 |
| Answer» x2 - kx + 9 = ax2 + bx + ca = 1 . b = -K and c = 9since the eqn has real roots∴ b²-4ac=0⇒ (-k)²-4×1×9=0⇒k²=√36⇒k=±6∵the smallest value of k is required∴k= -6 | |