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Find the sum 2,7,12,......,to 100 terms

Answer» Here\xa0a=2,n=100And\xa0d=7−2=5Sn\u200b= n/2 \u200b[2a+(n−1)d]S100 \u200b= 100/2 \u200b[2(2)+(100−1)5]\xa0= 50[4 + 495 ]= 50(499)=24950


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