1.

Find the sum of 0.6,1,7,2,8,....to 100 terms

Answer» Given AP: 0.6, 1.7, 2.8, ............\xa0a = 0.6d = 1.7 - 0.6 = 1.1n = 100Sn = n/2[ 2a + (n-1)d] = 100/2 [ 2(0.6) + (100 - 1)×(1.1)] = 50[ 1.2 + (99\xa0× 1.1)] = 50[ 1.2 + 108.9] =50[110.1] = 5505


Discussion

No Comment Found