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| 1. |
Find the sum of all 3 digit no. Which leave a remainder 3 when divided by 5 . |
| Answer» First 3 Digit Number that leaves remainder 3 when divided by 5 is 103.and last will be 998A.P. = 103, 108, 113, ..................., 998first term a = 103Common Difference d = 5nth term = 998n = ?as we knownth term = a + ( n-1)d998 = 103 + ( n-1)5895/ 5 = n -1179 = n -1n = 180\xa0now find sum of 180 terms of APS180 =\xa0180/ 2 ( 103 + 998 )=> S180 = 90\xa0* 1001=> S180 = 900090 | |